Cannot find file path startfile python

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August undefined, 2024

WebFeb 22, 2024 · I am trying to select a random music file from a folder in Python using the windows commands: random.choice () os.listdir () os.startfile () Here is the code: import … WebJun 2, 2024 · The system cannot find the file specified: 'PG2356E2-26.jpg' You are intending to operate on a path name (like "C:\PG2\356E2-26.jpg"), but are instead handing to rename () a string with all that mushed together. You didn't put any path separators in. You could do that manually, but better is to use os.path functions to form them. 1 2 3 4 5 …

python - FileNotFoundError: [WinError 2] The system cannot find …

WebApr 4, 2024 · os.startfile () path in python with numbers Ask Question Asked 6 years ago Modified 6 years ago Viewed 9k times 1 I am working on a little project in python for work. It involves opening a file with the os.startfile () And there in lies my problem : the path to the file contains several numbers. WebOct 28, 2024 · try this: import os from time import sleep os.startfile ('yourFile.xclx') sleep (4) os.system ('TASKKILL /F /IM EXCEL.EXE') # os.system ('TASKKILL /F /FI "WINDOWTITLE yourtitle"') link to the source Share Follow edited Oct 28, 2024 at 7:45 answered Oct 28, 2024 at 7:30 Matiiss 5,892 2 13 29 module 'os' has no attribute 'openfile' – Soother gold coast spit weather

python - Pathname too long to open? - Stack Overflow

WebSep 9, 2008 · It should be from path import Path then Path ('mydir/myfile.txt').abspath () – Frak Jun 5, 2024 at 14:51 1 There are no typos, you may have been using a different path module. The linked module uses a class named path. WebJul 3, 2016 · If you start the Python script from another directory, e.g. in a command prompt or the run dialog, then the working directory won't be the Python script directory, and startfile will fail. The VBS script also inherits this working directory. WebTo fix this, change the loop in your code to: for root, dirs, filenames in os.walk (folder): for filename in filenames: filename = os.path.join (root, filename) ... process file here. which … gold coast spit roast catering

How to get an absolute file path in Python - Stack Overflow

python - Subprocess.run() cannot find file, even if path.exists ...

WebFeb 22, 2024 · You can use glob.glob() to find files using wildcard instead of listing all the files and then go through the file list to find the required files. Also there is no xdg-open in Windows platform, use os.startfile() instead of subprocess.call(). WebDec 7, 2024 · Python's installer doesn't define "runas" for "Python.File", but you can create it by copying the "open" command. Then you can use os.startfile to run a script elevated, as long as it doesn't require command-line arguments. If you need command-line arguments, then you'll have to use PyWin32 or ctypes to call ShellExecute [Ex] directly. – Eryk Sun hcg of 4000WebJul 19, 2024 · If you want to open the KML file according to its registered file association, use os.startfile (lines_kml_flyingpath). Error while converting pdf to htmls using subprocess Almtein (Mtein) July 19, 2024, 4:00pm 7 I attached below the complete code, its small. Script * import simplekml import subprocess import pandas as pd hcg of 34

"WebOct 14, 2024 · import os file_name = raw_input("File Name: ") #file to be searched #cur_dir = raw_input("Search Directory: ") # Dir from where search starts can be replaced with … " - Cannot find file path startfile python

Cannot find file path startfile python

FileNotFoundError: [WinError 2] The system cannot find the file ...

WebJan 16, 2013 · If this is a Python 3 & unicode problem, I suggest trying to fix the string first: path = "\\\\myshare\folder" path = bytes (path, "utf-8").decode ("unicode_escape") print … WebOct 29, 2024 · os.startfile require file directory + file name (if your script not in the same directory with the files) import random import os himg = 'C:\\Users\\Vl\\Desktop\\aaaa\\himg\\' files = os.listdir (himg) d = random.choice (files) rng1 = (random.randint (0, 10)) if (rng1 % 2) == 0: os.startfile (himg + d) Share Improve this …

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WebDec 19, 2024 · 1 I saw a question on here somewhat like mine, but the solution there did not work. My code is: for filename in os.scandir ('\\\\network_drive\\folder\\folder\\folder\\'): print (filename) The error is: FileNotFoundError: [WinError 67] The network name cannot be found: '\\\\network_drive\\folder\\folder\\folder\\' WebJul 22, 2024 · However, looking at this question Open document with default OS application in Python, both in Windows and Mac OS you should use start instead of open for …

WebMar 21, 2024 · import os, sys, subprocess def open_file (filename): if sys.platform == "win32": os.startfile (filename) else: opener = "open" if sys.platform == "darwin" else "xdg-open" subprocess.run ( [opener, filename]) If your file is just a bash script, you can replace the subprocess.run line by subprocess.run ( ["bash", filename]) Share

WebOct 11, 2024 · Description What steps will reproduce the problem? 'conda create -n myenv spyder-kernels' in miniconda cmd 2)change default env in prefrences 3)restart console Traceback ERROR:traitlets:Failed to r... WebThe file itself is located in the same folder as the script file trying to open it: C:\Users\User\Desktop\Python stuff\Data.txt for simplicity, the simplest means to access the file (at least that I know of) is f=open These lines were coded as: f = open ("Data.txt", "r") and f = open ("C:/Users/User/Desktop/Python stuff/Data.txt", "r")

WebDec 28, 2014 · Solution: You need to set options {"enable-local-file-access": ""}. For example: pdfkit.from_string (_html, pdf_path, options= {"enable-local-file-access": ""}) – Milovan Tomašević Dec 21, 2024 at 21:44 Add a comment 2 You need set: pdfkit.from_url ('http://google.com', 'out.pdf',configuration=config) Share Improve this answer Follow

WebApr 10, 2015 · Use GetShortPathName from kernel32.dll and access the file in this way. That is nice, but I cannot use it, since I need to use the paths in a way shutil.rmtree … gold coast sport and recWebYou are using splitext to determine the source filename to rename: filename_split = os.path.splitext (filename) # filename and extensionname (extension in [1]) filename_zero = filename_split [0]# ... os.rename (filename_zero, filename_zero.replace ('+','_')) gold coast sport and recreationWebYou cannot use an absolute path, unless your terminal is in that directory. Hence, you can do as in the following: import os def rename(directory): os.chdir(directory) # Changing to … hcg of 45WebJul 19, 2024 · If os.startfile(lines_kml_flyingpath) raises FileNotFoundError, then it’s the KML file itself that can’t be found, as opposed to “open.exe” with the original subprocess … gold coast sport centreWebJul 31, 2024 · 2 Answers Sorted by: 1 You can try os.system with open. For example: os.system ("open Untitled.pdf") This will open the file Untitled.pdf with the default PDF application ('Preview', in my case). Share Improve this answer Follow answered Jul 31, 2024 at 15:33 Roy2012 11.5k 2 22 35 it's recommended to use subprocess over … hcg of 38WebMar 11, 2012 · There is this one part of my code that causes trouble. I try to open a file using the os.system ('gnome-open ' + filePath) command but I can't get it to open a file … gold coast sport field closuresWebMar 25, 2016 · Please make sure of the following: The parent directory of the folder (JSONFiles) is the same as the directory of the Python script. Even though the folder … hcg of 46